# FeO + H2SO4 → Fe2(SO4)3 + SO2 + H2O

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FeO + OR2THEREFORE4 → Fe2(THEREFORE)4)3 + SO2 + FRIENDS2O is a redox reaction compiled by Soc Trang High School, this equation will appear in the content of the lesson: Balancing redox reactions Chemistry 10, Chemistry 12: Lesson 32 Compounds of iron.. .. as well as exercises.

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## 2. FeO + H balance. reaction2THEREFORE4 → Fe2(THEREFORE)4)3 + SO2 + FRIENDS2UMBRELLA

Fe+2O + OR2S+6O4 → +3Fe2(THEREFORE)4)3 + S+4O2 + FRIENDS2UMBRELLA

You are viewing: FeO + H2SO4 → Fe2(SO4)3 + SO2 + H2O

 double 1x Fe+2 → Fe+3 +1e S+6 + 2e → S+4

2FeO + 4H2THEREFORE4 → Fe2(THEREFORE)4)3 + SO2+ 4 HOURS2UMBRELLA

Do not have

## 4. How to conduct the reaction for FeO to react with H . solution2THEREFORE4 thick hot

Let FeO react with sulfuric acid solution H2THEREFORE4 thick hot

## 5. Chemical Phenomena

When FeO reacts with acidic solution H2THEREFORE4 products that give iron(III) sulfate salts and have

sulfur dioxide gas with a pungent odor is released.

## 6. Chemical properties of FeO

Iron (II) compounds have both reducing and oxidizing properties, but the reducing property is more specific, because in chemical reactions Fe2+ ions easily yield 1e to Fe3+ ions:

Fe2+ ​​+ 1e → Fe3+

• The characteristic property of iron(II) compounds is reduction.

Iron(II) compounds are usually unstable and easily oxidized to iron(III) compounds.

FeO is a basic oxide, in addition, due to oxidation number +2 – intermediate oxidation number => FeO has reducing and oxidizing properties.

• FeO is a basic oxide:

Reaction with acidic solutions: HCl; H2THEREFORE4 wash…

FeO + 2HCl → FeCl2 + FRIENDS2

FeO + OR2THEREFORE4 dilution → FeSO4 + FRIENDS2UMBRELLA

• FeO is an oxidizing agent when reacted with a strong reducing agent: H2, CO, Al → Fe

FeO + OR2 ​Fe + H2UMBRELLA

FeO + CO Fe + CO2

3FeO + 2Al Al2UMBRELLA3 + 3Fe

• FeO is a reducing agent when reacting with a strong oxidizing agent: HNO3; H2THEREFORE4 special; UMBRELLA2

4FeO + O2 ​ 2Fe2UMBRELLA3

3FeO + 10HNO3 dilution → 3Fe(NO.)3)3 + NO + 5 HOURS2UMBRELLA

FeO + 4HNO3 thick, hot → Fe(NO.)3)3 + NO2 + 2 SMALL HOUSES2UMBRELLA

2FeO + 4H2THEREFORE4 thick, hot → Fe2(THEREFORE)4)3 + SO2 + 4 HOURS2UMBRELLA

## 7. Related Exercises

Question 1. Let 7.2 grams of FeO react completely with H . acid solution2THEREFORE4 hot, after the reaction, V liters of SO are obtained. get gas2 (single reduction product, dktc). The value of V is:

A. 1.12 liters

B. 2.24 liters

C. 3.36 liters

D. 4.48 liters

WOMENFeO = 0.1 mol

Reaction Equation:

2FeO + 4H2THEREFORE4 → Fe2(THEREFORE)4)3 + SO2+ 4 HOURS2UMBRELLA

0.1 → 0.05 mol

WOMENSO2 = 1/2 nFeO = 0.05 mol => VSO2 = 0.05.22.4 = 1.12 liters

Question 2. Which of the following compounds does not react with H?2THEREFORE4 thick cold?

A. Cu, Al, Fe

B. Al, Fe, Cr

C. Fe, Cu, Ag

D. Cr, Cu, Fe

Which of the following series of substances does not react with cold concentrated H2SO4: Al, Fe, Cr

Question 3. Which of the following ores has the highest Fe content?

A. Red Hematite

B. Pirit

C. Manheti

D. Siderit

A. Red hematite (Fe2UMBRELLA3).

. %mFe= (2.56)/(2.56 +3.16).100% = 70%

B. Pyrite (FeS2).

%mFe = 56/(56 + 2.32).100% = 46.67%

C. Manhetite (Fe3UMBRELLA4).

%mFe = 3.56/(3.56 + 4.16).100% = 72.41%

D. Ciderite (FeCO3).

%mFe = 56/(56 + 12 + 16.3).100% = 48.28%

So the ore with the highest Fe content is Fe.3UMBRELLA4

Question 4. Which of the following substances reacts with Fe without forming Fe(III) compounds?

A. OR solution2THEREFORE4 thick hot

B. HNO . solution3 dilution

C. AgNO solution3 residual

D. concentrated HCl solution

A. OR solution2THEREFORE4 hot

2Fe + 6H2THEREFORE4 → Fe2(THEREFORE)4)3 + 3SO2+ 6 HOUSES2UMBRELLA

B. HNO . solution3 wash

Fe + 4HNO3 → Fe(NO.)3)3 + NO + 2 HOUSES2UMBRELLA

C. AgNO solution3 residual

Fe + 3AgNO3 → Fe(NO.)3)3 +3Ag

D. concentrated HCl solution

Fe + 2HCl → FeCl2 + FRIENDS2

So reaction D produces iron salt II

Question 5. Let 5.4 grams of metal A completely dissolve in H2THEREFORE4 hot, after the reaction is completed, 6.72 liters of SO is obtained. get gas2 (only reduction product, at tc). That metal A is:

A. Fe

B. Al

C.Zn

D. Cu

Number of moles of SO2 Okay:

WOMENSO2 = V/22.4 = 6.72/22.4 = 0.3 (mol)

What is the reaction equation?

2R + 2nH2THEREFORE4(d) → CHEAP2(THEREFORE)4)n + nSO2+ 2nH2UMBRELLA

0.6/n 0.3

The molar mass of R is:

USACHEAP = m/n = 5.4/0.6/n = 9n

debatable

R is aluminum metal

Question 6. The main composition of hemantite ore is:

A. Fe3UMBRELLA4

B. Fe2UMBRELLA3

C. FeS2

D. Al2UMBRELLA3

The main component of hemantite ore is Fe.2UMBRELLA3.

Magnetite ore: Fe3UMBRELLA4

Iron pyrite ore: FeS2

Bauxite ore: Al2UMBRELLA3.

Question 7. A hemantite ore with 80% Fe3UMBRELLA4 used to produce cast iron containing 95% iron. If the efficiency of the reaction is 80%, then the mass of iron obtained from 150 tons of magnetite ore is

A. 63.81 tons

B. 71.38 tons

C. 73.18 tons

D. 78.13 tons

mass Fe3UMBRELLA4 in 150 tons of ore is: (80,150)/100 = 120 tons

Mass of Fe in 120 tons of Fe3UMBRELLA4: (120,168)/100 = 86.9 tons

The volume of cast iron obtained: (86,9,100)/95.(80/100) = 73.18 tons

Question 8. For 5.4 grams of a mixture of 2 metals Fe and Zn, react completely with 90 ml of 2M HCl solution. The mass of salt obtained is

A. 11.79 grams

B. 11.5 grams

C. 15.71 grams

D. 17.19 grams

WOMENHCl = 0.09. 2 = 0.18 (mol)

reaction equation

Zn + 2HCl → ZnCl2 + FRIENDS2

Fe + 2HCl → FeCl2 + FRIENDS2

From (1) and (2) nH2 = 1/2nHCl = 0.09 (mol)

According to the law of conservation of mass we have:

I mixture + m acid = m salt + m hydrogen

=> m salt = 5.4 + 0.18.36.5 – 0.09.2 = 11.79 grams

Question 9: Dissolve an iron oxide in H. solution2THEREFORE4 dilute solution X

Divide solution X into 2 equal parts:

Part 1: Add a little Cu and see that it is completely dissolved and the solution is blue

Part 2: Add a few drops of KMnO solution4 color loss.

iron oxide is

A. FeO.

B. Fe3UMBRELLA4.

C. Fe2UMBRELLA3 .

D. FeO or Fe2UMBRELLA3.

Solution X reacts with Cu → solution X contains Fe3+ . ions

Solution X reacts with KMnO4 → solution X contains Fe2+ ions

So iron oxide has the formula Fe3UMBRELLA4.

Question 10: Dissolve Fe3UMBRELLA4 into HCl solution to get solution X. Divide X into 3 parts:

Add excess NaOH to part 1 to precipitate Y. Take Y out into the air.

Add Cu powder to part 2.

Strength Cl2 into part 3.

In the above processes, the number of oxidation – reduction reactions is .

A.2.

B.3.

C.4.

D.5.

Fe3UMBRELLA4 + 8HCl → FeCl2 + 2FeCl3 + 4 HOURS2Box (1)

Part 1:

FeCl2 + 2NaOH → Fe(OH)2 + 2NaCl (2)

FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl (3)

4Fe(OH)2 + Oh2 + 2 SMALL HOUSES2O → 4Fe(OH)3 (4)

Part 2:

2FeCl3 + Cu → 2FeCl2 + CuCl2 (5)

Part 3:

2FeCl2 + Cl2 → 2FeCl3 (6)

The redox reactions are: (4), (5), (6).

Question 11. Which of the following statements is correct?

A. Cast iron is an alloy of iron with carbon and some other elements, in the composition of carbon accounting for 2 to 5%.

B. Cast iron is an alloy of iron with carbon and some other elements, in a carbon content greater than 5%.

C. Cast iron is an alloy of aluminum with carbon and some other elements, in the composition of carbon accounting for 2 to 5%.

D. Cast iron is an alloy of aluminum with carbon and some other elements, in which the carbon content is greater than 5%.

Cast iron is an alloy of iron with carbon and some other elements, in the composition of carbon accounting for 2 to 5%.

Question 12. A hemantite ore with 80% Fe3UMBRELLA4 used to produce cast iron containing 95% iron. If the efficiency of the reaction is 80%, then the mass of iron obtained from 150 tons of magnetite ore is

mass Fe3UMBRELLA4 in 150 tons of ore is: (80,150)/100 = 120 tons

Mass of Fe in 120 tons of Fe3UMBRELLA4: (120,168)/100 = 86.9 tons

The volume of cast iron obtained: (86,9,100)/95.(80/100) = 73.18 tons

Question 14. Perform experiments on the following reaction:

(1) Burning iron wire in Cl. gas2 residual

(2) Add Iron to HNO. solution3 thick, cold

(3) Put the iron rod in dilute HCl solution, excess

(4) Add iron to H solution2THEREFORE4 dilution, excess

(5) Add iron to H solution2THEREFORE4 thick, hot

The number of experiments to create Fe(II) salt is:

A. 3

B 4

C. 2

D.1

2Fe + 3Cl2 → 2FeCl3

Fe + HNO3 special cold dishes → no response

Fe + 2HCl → FeCl2 + FRIENDS2

Fe + H2THEREFORE4 → FeSO4 + FRIENDS2

2Fe + 6H2THEREFORE4 → Fe2(THEREFORE)4)3 + 3SO2 + 6 HOUSES2UMBRELLA

Question 15. Add a gram of Zn powder to 200 ml of Fe solution. solution2(THEREFORE)4)3 0.3M. After the reactions are complete, the mass of the solution increases by 4.26 grams compared to the original solution. What is the value of a:

A. 3.25.

B. 8.45.

C. 4.53.

D. 6.5.

WOMENFe2(SO4)3 = 0.06 mol

→nFe3+ = 0.12 mol

Zn + 2Fe3+ → Zn2+ + 2Fe2+ (1)

Zn + Fe2+ → Zn2+ + Fe (2)

According to (1): nZn = 1/2nFe3+ = 0.06 mol

Set nFe birth = x mol => nZn (2) = x moles

Isolution increase = mZn – mFe = 4.26

=> 0.06.65 + 65x – 56x = 4.26 => x = 0.04

=> mZn = mZn (1) + mZn (2) = 65.(0.06 + 0.04) = 6.5 grams

……………………

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Soc Trang High School sends you the chemical equation FeO + H2THEREFORE4 → Fe2(THEREFORE)4)3 + SO2 + FRIENDS2O compiled by Soc Trang High School is a redox reaction, the opposite reaction when iron (II) oxide is reacted with H acid solution.2THEREFORE4 When heated, the product obtained is iron (III) sulfate salt and has a strong odor SO .2.

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