FeO + H2SO4 → Fe2(SO4)3 + SO2 + H2O

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FeO + OR₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + SO₂ + FRIENDS₂O is a redox reaction compiled by Soc Trang High School, this equation will appear in the content of the lesson: Balancing redox reactions Chemistry 10, Chemistry 12: Lesson 32 Compounds of iron.. .. as well as exercises.

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1. Equation of the reaction FeO reacts with H₂THEREFORE₄ special

2FeO + 4H₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + SO₂+ 4 HOURS₂UMBRELLA

2. FeO + H balance. reaction₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + SO₂ + FRIENDS₂UMBRELLA

Fe+2O + OR₂S+6O₄ → +3Fe₂(THEREFORE)₄)₃ + S+4O₂ + FRIENDS₂UMBRELLA

You are viewing: FeO + H2SO4 → Fe2(SO4)3 + SO2 + H2O

double 1x

Fe+2 → Fe+3 +1e S+6 + 2e → S+4

2FeO + 4H₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + SO₂+ 4 HOURS₂UMBRELLA

3. Reaction conditions FeO reacts with H . solution₂THEREFORE_{4 thick hot}

Do not have

4. How to conduct the reaction for FeO to react with H . solution₂THEREFORE_{4 thick hot}

Let FeO react with sulfuric acid solution H₂THEREFORE_{4 thick hot}

5. Chemical Phenomena

When FeO reacts with acidic solution H₂THEREFORE₄ products that give iron(III) sulfate salts and have

sulfur dioxide gas with a pungent odor is released.

6. Chemical properties of FeO

Iron (II) compounds have both reducing and oxidizing properties, but the reducing property is more specific, because in chemical reactions Fe2+ ions easily yield 1e to Fe3+ ions:

Fe2+ ​​+ 1e → Fe3+

• The characteristic property of iron(II) compounds is reduction.

Iron(II) compounds are usually unstable and easily oxidized to iron(III) compounds.

FeO is a basic oxide, in addition, due to oxidation number +2 – intermediate oxidation number => FeO has reducing and oxidizing properties.

• FeO is a basic oxide:

Reaction with acidic solutions: HCl; H₂THEREFORE₄ wash…

FeO + 2HCl → FeCl₂ + FRIENDS₂

FeO + OR₂THEREFORE_{4 dilution} → FeSO₄ + FRIENDS₂UMBRELLA

• FeO is an oxidizing agent when reacted with a strong reducing agent: H_2, CO, Al → Fe

FeO + OR₂​Fe + H₂UMBRELLA

FeO + CO Fe + CO₂

3FeO + 2Al Al₂UMBRELLA₃ + 3Fe

• FeO is a reducing agent when reacting with a strong oxidizing agent: HNO₃; H₂THEREFORE_{4 special}; UMBRELLA₂…

4FeO + O₂​ 2Fe₂UMBRELLA₃

3FeO + 10HNO_{3 dilution} → 3Fe(NO.)₃)₃ + NO + 5 HOURS₂UMBRELLA

FeO + 4HNO_{3 thick, hot} → Fe(NO.)₃)₃ + NO₂ + 2 SMALL HOUSES₂UMBRELLA

2FeO + 4H₂THEREFORE_{4 thick, hot} → Fe₂(THEREFORE)₄)₃ + SO₂ + 4 HOURS₂UMBRELLA

7. Related Exercises

Question 1. Let 7.2 grams of FeO react completely with H . acid solution₂THEREFORE₄ hot, after the reaction, V liters of SO are obtained. get gas₂ (single reduction product, dktc). The value of V is:

A. 1.12 liters

B. 2.24 liters

C. 3.36 liters

D. 4.48 liters

Answer A

WOMEN_FeO = 0.1 mol

Reaction Equation:

2FeO + 4H₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + SO₂+ 4 HOURS₂UMBRELLA

0.1 → 0.05 mol

WOMEN_SO2 = 1/2 n_FeO = 0.05 mol => V_SO2 = 0.05.22.4 = 1.12 liters

Question 2. Which of the following compounds does not react with H?₂THEREFORE₄ thick cold?

A. Cu, Al, Fe

B. Al, Fe, Cr

C. Fe, Cu, Ag

D. Cr, Cu, Fe

The answer is no

Which of the following series of substances does not react with cold concentrated H2SO4: Al, Fe, Cr

Question 3. Which of the following ores has the highest Fe content?

A. Red Hematite

B. Pirit

C. Manheti

D. Siderit

OLD ANSWERS

A. Red hematite (Fe₂UMBRELLA₃).

. %m_Fe= (2.56)/(2.56 +3.16).100% = 70%

B. Pyrite (FeS₂).

%m_Fe = 56/(56 + 2.32).100% = 46.67%

C. Manhetite (Fe₃UMBRELLA₄).

%m_Fe = 3.56/(3.56 + 4.16).100% = 72.41%

D. Ciderite (FeCO₃).

%m_Fe = 56/(56 + 12 + 16.3).100% = 48.28%

So the ore with the highest Fe content is Fe.₃UMBRELLA₄

Question 4. Which of the following substances reacts with Fe without forming Fe(III) compounds?

A. OR solution₂THEREFORE_{4 thick hot}

B. HNO . solution_{3 dilution}

C. AgNO solution₃ residual

D. concentrated HCl solution

EASY ANSWER

A. OR solution₂THEREFORE₄ hot

2Fe + 6H₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + 3SO₂+ 6 HOUSES₂UMBRELLA

B. HNO . solution₃ wash

Fe + 4HNO₃ → Fe(NO.)₃)₃ + NO + 2 HOUSES₂UMBRELLA

C. AgNO solution₃ residual

Fe + 3AgNO₃ → Fe(NO.)₃)₃ +3Ag

D. concentrated HCl solution

Fe + 2HCl → FeCl₂ + FRIENDS₂

So reaction D produces iron salt II

Question 5. Let 5.4 grams of metal A completely dissolve in H₂THEREFORE₄ hot, after the reaction is completed, 6.72 liters of SO is obtained. get gas₂ (only reduction product, at tc). That metal A is:

A. Fe

B. Al

C.Zn

D. Cu

The answer is no

Number of moles of SO₂ Okay:

WOMEN_SO2 = V/22.4 = 6.72/22.4 = 0.3 (mol)

What is the reaction equation?

2R + 2nH₂THEREFORE₄(d) → CHEAP₂(THEREFORE)₄)n + nSO₂+ 2nH₂UMBRELLA

0.6/n 0.3

The molar mass of R is:

USA_CHEAP = m/n = 5.4/0.6/n = 9n

debatable

R is aluminum metal

Question 6. The main composition of hemantite ore is:

A. Fe₃UMBRELLA₄

B. Fe₂UMBRELLA₃

C. FeS₂

D. Al₂UMBRELLA₃

The answer is no

The main component of hemantite ore is Fe.₂UMBRELLA₃.

Magnetite ore: Fe₃UMBRELLA₄

Iron pyrite ore: FeS₂

Bauxite ore: Al₂UMBRELLA₃.

Question 7. A hemantite ore with 80% Fe₃UMBRELLA₄ used to produce cast iron containing 95% iron. If the efficiency of the reaction is 80%, then the mass of iron obtained from 150 tons of magnetite ore is

A. 63.81 tons

B. 71.38 tons

C. 73.18 tons

D. 78.13 tons

OLD ANSWERS

mass Fe₃UMBRELLA₄ in 150 tons of ore is: (80,150)/100 = 120 tons

Mass of Fe in 120 tons of Fe₃UMBRELLA₄: (120,168)/100 = 86.9 tons

The volume of cast iron obtained: (86,9,100)/95.(80/100) = 73.18 tons

Question 8. For 5.4 grams of a mixture of 2 metals Fe and Zn, react completely with 90 ml of 2M HCl solution. The mass of salt obtained is

A. 11.79 grams

B. 11.5 grams

C. 15.71 grams

D. 17.19 grams

Answer A

WOMEN_HCl = 0.09. 2 = 0.18 (mol)

reaction equation

Zn + 2HCl → ZnCl₂ + FRIENDS₂

Fe + 2HCl → FeCl₂ + FRIENDS₂

From (1) and (2) n_H2 = 1/2n_HCl = 0.09 (mol)

According to the law of conservation of mass we have:

I _mixture + m _acid = m _salt + m _hydrogen

=> m _salt = 5.4 + 0.18.36.5 – 0.09.2 = 11.79 grams

Question 9: Dissolve an iron oxide in H. solution₂THEREFORE₄ dilute solution X

Divide solution X into 2 equal parts:

Part 1: Add a little Cu and see that it is completely dissolved and the solution is blue

Part 2: Add a few drops of KMnO solution₄ color loss.

iron oxide is

A. FeO.

B. Fe₃UMBRELLA₄.

C. Fe₂UMBRELLA₃ .

D. FeO or Fe₂UMBRELLA₃.

The answer is no

Solution X reacts with Cu → solution X contains Fe3+ . ions

Solution X reacts with KMnO₄ → solution X contains Fe2+ ions

So iron oxide has the formula Fe₃UMBRELLA₄.

Question 10: Dissolve Fe₃UMBRELLA₄ into HCl solution to get solution X. Divide X into 3 parts:

Add excess NaOH to part 1 to precipitate Y. Take Y out into the air.

Add Cu powder to part 2.

Strength Cl₂ into part 3.

In the above processes, the number of oxidation – reduction reactions is .

A.2.

B.3.

C.4.

D.5.

The answer is no

Fe₃UMBRELLA₄ + 8HCl → FeCl₂ + 2FeCl₃ + 4 HOURS₂Box (1)

Part 1:

FeCl₂ + 2NaOH → Fe(OH)₂ + 2NaCl (2)

FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl (3)

4Fe(OH)₂ + Oh₂ + 2 SMALL HOUSES₂O → 4Fe(OH)₃ (4)

Part 2:

2FeCl₃ + Cu → 2FeCl₂ + CuCl₂ (5)

Part 3:

2FeCl₂ + Cl₂ → 2FeCl₃ (6)

The redox reactions are: (4), (5), (6).

Question 11. Which of the following statements is correct?

A. Cast iron is an alloy of iron with carbon and some other elements, in the composition of carbon accounting for 2 to 5%.

B. Cast iron is an alloy of iron with carbon and some other elements, in a carbon content greater than 5%.

C. Cast iron is an alloy of aluminum with carbon and some other elements, in the composition of carbon accounting for 2 to 5%.

D. Cast iron is an alloy of aluminum with carbon and some other elements, in which the carbon content is greater than 5%.

Answer A

Cast iron is an alloy of iron with carbon and some other elements, in the composition of carbon accounting for 2 to 5%.

Question 12. A hemantite ore with 80% Fe₃UMBRELLA₄ used to produce cast iron containing 95% iron. If the efficiency of the reaction is 80%, then the mass of iron obtained from 150 tons of magnetite ore is

OLD ANSWERS

mass Fe₃UMBRELLA₄ in 150 tons of ore is: (80,150)/100 = 120 tons

Mass of Fe in 120 tons of Fe₃UMBRELLA₄: (120,168)/100 = 86.9 tons

The volume of cast iron obtained: (86,9,100)/95.(80/100) = 73.18 tons

Question 14. Perform experiments on the following reaction:

(1) Burning iron wire in Cl. gas₂ residual

(2) Add Iron to HNO. solution₃ thick, cold

(3) Put the iron rod in dilute HCl solution, excess

(4) Add iron to H solution₂THEREFORE₄ dilution, excess

(5) Add iron to H solution₂THEREFORE₄ thick, hot

The number of experiments to create Fe(II) salt is:

A. 3

B 4

C. 2

D.1

OLD ANSWERS

2Fe + 3Cl₂ → 2FeCl₃

Fe + HNO_{3 special cold dishes} → no response

Fe + 2HCl → FeCl₂ + FRIENDS₂

Fe + H₂THEREFORE₄ → FeSO₄ + FRIENDS₂

2Fe + 6H₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + 3SO₂ + 6 HOUSES₂UMBRELLA

Question 15. Add a gram of Zn powder to 200 ml of Fe solution. solution₂(THEREFORE)₄)₃ 0.3M. After the reactions are complete, the mass of the solution increases by 4.26 grams compared to the original solution. What is the value of a:

A. 3.25.

B. 8.45.

C. 4.53.

D. 6.5.

EASY ANSWER

WOMEN_Fe2(SO4)3 = 0.06 mol

→n_Fe3+ = 0.12 mol

Zn + 2Fe3+ → Zn2+ + 2Fe2+ (1)

Zn + Fe2+ → Zn2+ + Fe (2)

According to (1): n_Zn = 1/2nFe3+ = 0.06 mol

Set n_Fe birth = x mol => n_Zn (2) = x moles

I_{solution increase} = m_Zn – m_Fe = 4.26

=> 0.06.65 + 65x – 56x = 4.26 => x = 0.04

=> m_Zn = m_{Zn (1)} + m_{Zn (2)} = 65.(0.06 + 0.04) = 6.5 grams

……………………

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Soc Trang High School sends you the chemical equation FeO + H₂THEREFORE₄ → Fe₂(THEREFORE)₄)₃ + SO₂ + FRIENDS₂O compiled by Soc Trang High School is a redox reaction, the opposite reaction when iron (II) oxide is reacted with H acid solution.₂THEREFORE₄ When heated, the product obtained is iron (III) sulfate salt and has a strong odor SO .₂.

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